(19/10)^x=2

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Solution for (19/10)^x=2 equation: 



(19/10)^x=2

We move all terms to the left:

(19/10)^x-(2)=0



Domain of the equation: 10)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+19/10)^x-2=0

We multiply all the terms by the denominator


(+19-2*10)^x=0

We add all the numbers together, and all the variables

(-1)^x=0

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